The ratio between the school ages of Neelam and Shaan is 5 : 6 respectively. If the ratio between the one-third age of Neelam and half of Shaan’s age is 5 : 9, then what is the school age of Shaan ?

\par Let the school ages of Neelam and Shaan be 5x and 6x years respectively.

\frac{\frac{1}{3} \times 5x}{\frac{1}{2} \times 6x} = \frac{5}{9}

(\frac{1}{3}\times 9\times 5x) = (\frac{5}{2}\times 6x)

15 = 15

\par Thus, Shaan's age cannot be determined.