# The present ages of three persons are in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).

$\par&space;Let&space;their&space;present&space;ages&space;be&space;4x,&space;7x&space;and&space;9x&space;years&space;respectively.$

$\par&space;(4x&space;-&space;8)&space;+&space;(7x&space;-&space;8)&space;+&space;(9x&space;-&space;8)&space;=&space;56$

$20x&space;=&space;80$
$x&space;=&space;4$

$\par&space;So,&space;their&space;present&space;ages&space;are&space;16&space;years,&space;28&space;years&space;and&space;36&space;years.$