# 180 meter long train crosses a man standing on the platform in 6 seconds. What is the speed of the train ?

$\par&space;Speed&space;=$ $\frac{Distance}{Time}$ $=&space;\frac{180}{6}&space;=&space;30$ meters

$30&space;\times&space;\frac{18}{5}&space;=&space;108$ km/hr